Alan Cross

May 28th, 2010

Hybrid Vehicle Using Mechanical Energy Storage

By Alan Cross, M.S.ChE..

Introduction
The performance characteristics and energy consumption of a proposed mechanical hybrid vehicle were investigated; the hybrid consisted of an internal combustion engine and a flywheel rotational energy storage device. Four operating modes were envisioned for the system: a start-up mode in which the flywheel would be brought to operational speed if it was not already at that speed, an acceleration mode in which the vehicle would be accelerated to cruising speed, a cruising mode in which the vehicle would travel at constant speed for a period of time, and a braking mode in which the vehicle would decelerate from cruising speed to a full stop and enter into an idling mode; in the braking mode, the vehicle would remain stationary for a period of time with the engine turned off, conserving fuel and significantly reducing atmospheric pollution. The vehicle then would reenter the acceleration mode, beginning a new cycle of accelerating, cruising, braking, and idling.

The purpose of the investigation was to determine whether the proposed vehicle would be competitive with, more energy-efficient than, and less polluting than a conventional vehicle driven only by an internal combustion engine. Improved energy efficiency of the hybrid would be achieved by storing energy in the flywheel while the vehicle was in a braking mode; in this mode, energy ordinarily is lost because of the generation of frictional heat in the braking system, as is the case with a conventional vehicle. Currently available electric-hybrid vehicles achieve similar efficiency improvements by using an internal combustion engine, electric motors for propulsion, and batteries for electrical storage.

Flywheel Mechanics
The flywheel selected for the mechanical hybrid vehicle considered in this investigation had minimal size and weight and a peak design rotational speed consistent with the maximum allowable tensile stress of the flywheel material. The resultant flywheel was 18 inches in diameter and 6 inches wide, fabricated of structural steel material, with a yield stress of 30,000 PSI, an ultimate tensile stress of 60,000 PSI, a weight of 442 pounds, a maximum rotational speed of  2100 RPM, a maximum tensile stress of 3050 PSI, and a resultant safety factor of 10:1, based on the yield stress. With this flywheel it was possible to accelerate the vehicle to 40 MPH in 10.5 seconds, with the flywheel rotational velocity decreasing from 2100 to 1000 RPM in the process.

The relationship between the rotational speed and maximum tensile stress of the flywheel was obtained as follows:

dF = (dW)fw(Vmax)²/(g)(R)
V = (RPM)max(Pi)(2)(R)/(60)
dW = 2(Pi)(R)(dR)(t)(Density)fw
dF = 8(Pi)³(R)²(dR)(t)(Density)fw(RPM)²/(3600)(g)

Combining the above and integrating yields the following:

Fmax = (8)(Pi)³(R)³(t)(Density)fw(RPMmax)²/(3)(3600)(g)                (1)
Smax = Fmax/(Dmax)(t)(144)                                                        (2)

Energy absorbed or recovered from the flywheel is obtained as follows:

dE = (dW)(V)²/(2)(g)
V = (RPM)(Pi)(D)/(60)
dW=(Pi)(D)(dD)(t)(Density)fw
dE = (t)(Density)fw(Pi)³(D)³(dD)(RPM)²/(2g)(3600)

Combining and integrating these equations gives the following net energy for a flywheel in which the initial rotational speed differs from the final rotational operating speed:

Efw = (t)(Density)fw(Pi)³((RPM)i)² – (RPM)f)² ))(D)4/(4)(2g)(3600)            (3)

Flywheel energy loss resulting from air friction is obtained as follows:

dE = (dF)(V)²/(2g)
V = (RPM)(2)(Pi)(R)/(60)
dF = (Cd)(V)²(2)(Pi)(R)(dR)(2))(Density)air/(2)(g)

Combining and integrating these equations yields the following:

Eaf = (Cd)(RPM)4((2)(Pi))5(R)6(2)(Density)air/(2g)² (60)4(6)                (4)

Flywheel power loss resulting from roller bearing friction is as follows:

Pbf = (Cf)(Wfw)(2)(Pi)(Rb)(RPM)                                                         (5)

Mechanical Hybrid Component Arrangement and Operating Modes
The schematic arrangement of the hybrid components and operating modes are shown in Figure 1. A description of the itemized components is given in Table 1.

Figure 1. Schematic Diagram of Components
and Operating Modes for Mechanical Hybrid


Table 1: Mechanical Hybrid Components

Item Number Description
1 Friction clutch, hydraulically opened or closed by on-off solenoid valve.
2, 3, 4 Same as item 1
5 Structural steel flywheel, 18 inch outside diameter and 6 inches thick
6, 7 Flud torque converters
8 Multivariable transmission
9 25-horsepower internal combusion engine
10 Front wheels with friction braking, driven by engine or flywheel
11 Drive belts and sprockets
12 Unpowered rear wheels with friction breaking
13 Sequencing of the components for the varios operating modes controlles by a programmable logic controller

Comparative Energy Requirements for Mechanical Hybrid and Conventional Vehicles
Equations for determining energy requirements for charging, acceleration, cruising, and braking operating modes are as follows:

Charging:             See Equation 3
Acceleration: (Eacc) = – ((Wv)(Vv)²/(2)(g) + (Rv)(Lacc))       (6)
(Rv) = –(((Cv)(Vv)²(Density)air)(Av)/(2)(g)) + ((Cvr)(Wv)))    (7)
Cruising: (Ecruise) = –((HP)(33,000)(Tcruise) + (Rv)(Lcruise))  (8)
Braking: (Ebraking) = (–Eacc)  (9)

Calculated data based on these equations are given in Table 2

Table 2: Energy Requirements and Operating Data
(Measurements in Foot-Pounds)

Mechanical Hybrid Conventional
Operating Mode 1, charging -186,500 0
Operation Mode 2, accelerating -144,200 -111,400
Operating Mode 3, cruising -825,000 -825,000
Operating Mode 4, braking +144,200 -111,400
Net energy requirements
exclusive of charging
-825,000 ft-lbs -1,050,000 ft-lbs.

Summary
This article has shown that a conventional nonhybrid vehicle powered by a 25-HP internal combustion engine and weighing 1500 pounds is more fuel-efficient than a mechanical hybrid weighing 1,942 pounds inclusive of an energy storage flywheel weighing 442 pounds and powered by an internal combustion engine with the same horsepower. Thus, on a trip totaling 75 miles in which the vehicles brake to a stop every 5 minutes, after cruising at 40 MPH, the mileage per gallon of fuel is 49.6 MPG, based on a fuel heating value of 145,000 BTU per gallon and an engine efficiency of 25%, for the conventional vehicle compared with 39.4 MPG for the hybrid, which travels a total of 58 miles at the same cruising speed and the same time interval before braking; this is a miles per gallon difference of about 25% in favor of the conventional vehicle. On shorter trips totaling 12 miles for the hybrid and 16 miles for the nonhybrid in which the vehicles brake to a stop every minute, the miles per gallon figure  is only 8% greater for the conventional vehicle.

The lesser fuel efficiency of the hybrid is due in part to its greater weight and in part to the need for mechanical recharging of the flywheel before each trip if the vehicle has remained idle for a significant time interval before beginning a trip; the flywheel will lose its charge, with RPM decreasing from a maximum operating speed of 2100 to 0 RPM, in about 2 hours, mainly as a result of roller bearing friction. Recharging to maximum operating speed with the internal combustion engine would require 14 seconds.

Hybrid fuel efficiency could be improved somewhat by reducing flywheel weight and increasing operating speed. However, reducing the flywheel weight by a factor of 2 would require an increase in operating speed by a factor of 4 to 8000 RPM. This could prove hazardous, however, if the wheel fragments or breaks away from its drivetrain.

Nomenclature
Av = frontal cross-sectional area of vehicle, square feet
Cv = vehicle drag coefficient, unitless, = 1.0
Cvr = coefficient of wheel rolling friction, unitless = 0.03
Cd = flywheel air drag coefficient, unitless = 0.005
Cf = coefficient of flywheel roller bearing friction, unitless = 0.003
D = flywheel diameter, feet
Density = pounds per cubic foot
E = energy absorbed or released, foot-pounds
F = centrifugal force, pounds
g = acceleration of gravity, feet/(sec)²
HP = internal combustion engine horsepower, (foot-pounds)/minute
Lacc = vehicle travel distance during acceleration = 300 feet
Lcruise = vehicle travel distance during cruising, feet
MPG = fuel consumption, miles per gallon of fuel
MPH = miles per hour
Pbf = flywheel power loss resulting from air and bearing friction, foot-pounds/minute
R = flywheel radius, feet
Rb = outside radius of flywheel bearing, feet
Rv = vehicle linear resistance to motion, pounds
RPM = flywheel rotational speed, revolutions/minute
S = flywheel tensile stress, PSI
T = cruise time, minutes
t = flywheel thickness, feet
V = velocity, feet/ second
W = weight, pounds

Subscripts

i = initial
f = final
max = maximum
fw = flywheel
air = ambient surroundings
af = air friction
acc = acceleration mode
cruise = cruise mode
braking = braking mode
v = vehicle

9 Responses to “Hybrid Vehicle Using Mechanical Energy Storage”

  1. Emmett R. Miller, P.E. Says:

    Mr. Cross,

    How would the flywheel be mounted so as to deal with precession and still be coupled to the drive train?

  2. Alan Cross Says:

    Mr. Miller, P.E.

    The horizontal fly wheel shaft would be parallel to the axis of the wheels and the shaft bearings would be fixed at either end to the car body, the flywheel and drive train behaving as a single unit. When going around a curve any tendency for the car to rotate about a horizontal axis perpendicular to the fly wheel shaft, that is for one side of the car to lift off its wheels would be negated by the weight of the car and a flywheel counter – rotational moment perpendicular to the plane of the flywheel. Similarly any tendency for the car to rotate about a vertical axis perpendicular to the flywheel shaft would be negated by frictional forces between the tires and pavement, due to the weight of the car and the coefficient of friction.

    Alan,

    Alan Cross

  3. Alan Cross Says:

    Mr. Miller, P.E.

    The following is an update of my message of June 11.

    Calculations were made to determine under what set of operating conditions the hybrid car, as described in the article, would not skid sideways when making a turn. The data used were as follows:

    Car dimensions: 5 ft. wideX5ft.highX10ft. long
    Center of gravity: geometric center
    Weight of flywheel and car and rotational speed of flywheel: As described in article
    Turning radius:200 feet
    Angle of the flywheel axle: Assumed = to 0.25 inches, due to the effects of centrifugal force on the car. This dimension will vary depending on tire pressure and tire dimensions.
    Speed of car 40 MPH.

    Calculated data were as follows:

    Flywheel horizontal force component and moment: (675lbs)(1.5ft.)
    Centrifugal force and moment: (1062lbs)(2.5 ft.)
    Weight and moment: (1900 lbs)(2.5 ft.)

    For equilibrium clockwise and counterclockwise moments must = 0 with the result that a 1467 lb force is less than the 1900 lb. weight force so that there will be no rotation of the car.

    Furthermore the friction between pavement and rubber tires will be the (1900 lb weight force)(0.8 the friction coefficient), or 1467 lbs. which is greater than the centrifugal force of 1060 lbs.

    Therefore the the car will not skid sideways.

    Alan,

    Alan Cross

  4. Alan Cross Says:

    Mr. Miller, PE

    My message of June 15 requires some further explanation, The moment balance should be obtained as follows:

    Radial force due to rotation of flywheel = (3000 PSI)(18)(6) = F fw, See dimensional data and flywheel stress in article

    The momentum balance with proper signs is therefore:

    -(1.5)(324,000)(sin flywheel shaft angle)- (centrifugal farce acting on car)(2.5) + (1900)(2.5) = 0

    Solving the above, results in an angle of the flywheel axle with the horizonatal equal to 0.24 degrees

    Furthermaore one wheel of the car is 1/4 inch higher than the wheel opposite

    Wheel friction due to the weight of the car is 1520 lbs ,which is greater than the centrifugal force acting on the car equal to 1062 pounds. Therefore the car will not skid sidewards when the turning radius is 200 feet.

    Alan,

    Alan Cross

  5. Jim Says:

    Hi

    Are you aware of the Hybrid system using a (Flybrid) flywheel & a (Torotrak) cvt transmission – manufactured by (Xtrac)
    The TOTAL weight of the flywheel and the cvt transmission is just 25kg – 55lbs
    A lot less than the 442 pounds in your example.

    • A flywheel made of steel and carbon fibre which rotated at over 60,000 RPM inside an evacuated chamber
    • 60 kW power transmission in either storage or recovery
    • 400 kJ of usable storage (after accounting for internal losses)

    Gyroscopic forces are proportional to rotational speed and inertia so although our flywheel speed is high our mass is very low and consequently the forces are low. For the Formula One system the maximum torque experienced on the track is expected to be less than 130 NM.

    The flywheel will slow down due to friction in the bearings and seals but because it runs in a vacuum the losses are low. The losses equate to around 2% of stored energy per minute but in normal road use this is no concern as the 95th percentile stop time is only 55 seconds.

    http://www.torotrak.com/pdfs/literature/KERS_CVT_brochure.pdf

    http://www.flybrid.co.uk/F1System.htm

    lhttp://www.xtrac.com/pdfs/Torotrak_Xtrac_CVT.pdf

    Regards

    Jim

  6. Alan Cross Says:

    Hello Jim

    I was unaware of the Flybrid flywheel and its mechanical characteristics and performance, as detailed in the websites you have been kind enough to provide.

    I believe that one of the reasons for the relatively poor performance I have calculated for the mechanical hybrid discussed in my article, compared to those using your high speed, low weight, vacuum enclosed Flybrid flywheel, is the lesser weight of the latter.

    The reasons I had opted to use a heavy, low speed flywheel in my analysis is that the low speed, 2100 RPM, steel flywheel, reduced air friction losses and did not pose a risk to occupants of the hybrid in the event of flywheel or shaft failure. I realize that because of the much lesser weight of your flywheel, the risk is no doubt considerably reduced despite its high speed, 65000 RPM. I have yet to determine the destructive power of flywheel failure, except to compare the total energy in the fragments due to their speed. In this regard, have you ever rotated your flywheel to destruction, to determine if the flywheel enclosure is able to contain the fragments?

    I thank you for the information you have already provided and ask that you contact me if you have any interest in having me do any analytical work in connection with your equipment or have any problems for which you are seeking a solution. As an example, I have made what I consider some logical replys to questioners comments regarding the effects of gyroscopic action on high speed movement of a mechanical hybrid.

    Regards,

    Alan

  7. Rebecca Burnet Says:

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  9. Amanda Moreno Says:

    What is the idea? It looks like your post got cut off…

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